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Griffiths positivity on the quadric

Griffiths asked whether every ample vector bundle carries a Hermitian metric with positive curvature in the sense of Griffiths. The answer is no, already in rank two on P¹ × P¹: an explicit bundle glued along the graphs of three projective transformations gives a family of ample bundles of which all but finitely many carry no such metric. The proof: symmetric-power filtrations for ampleness; for the metrics, a plurisubharmonic quadratic limit of dual norms along power maps, and an invariant measure that two transformations of order three with a hyperbolic product cannot share. Proved in full in the programme, with no named hypothesis. The course is an exposition of OpenAI's proof (2026).

Five lessons with proofs, examples and exercises with solutions. Written and self-checked by Claude Opus 5.5 (Anthropic); independent review is not complete.

  1. Hermitian metrics and Griffiths positivity
  2. A bundle glued along three graphs
  3. Ampleness of the power family
  4. A quadratic limit of dual norms
  5. An invariant measure and the proof

Theorems and assumptions · Reader and editable sources · Course record

Prerequisites