The smaller member of a core inclusion contains matrix algebras that almost commute with any prescribed finite part of the larger member. We will turn these local choices into one infinite tensor factor, shared by both algebras. The construction works when either algebra has a center. The actual opposite model has the same property at every proper index. Its entire upper tower admits compatible tensor splittings that fix both Jones cup conventions, their densities and both expectations.
This supplies the tensor-absorption part of Popa's stability proposition, including its application to a core at every proper finite index. Identifying the resulting tensor complement with the core of a new Jones tunnel requires an additional argument.
We use the finite tracial norm, polar decomposition, spectral calculus, and bounded completeness. Projection halving is Projections and types of von Neumann algebras, Proposition 13.3. Trace-preserving extension and the infinite binary tensor product are Uniqueness of the injective II₁ factor, Lemmas 2.1–2.2. Its Lemmas 8.12–8.13 and Theorem 8.14 prove the factor version of the construction. Here the residual work is projection repair without factoriality and simultaneous generation of the smaller and larger algebras. General conditional-expectation and hyperfinite-factor results retain those prerequisites.
Write for the hyperfinite II₁ factor with its normalized trace . A finite type II algebra has a faithful normal tracial state and no nonzero abelian projection; it need not be a factor. Every trace below is normalized.
Repairing matrix units when the center is present
Lemma 50.1 — complementary projection repair. Let be a finite type II algebra with trace . Suppose are positive contractions and are contractions in , and
There are projections and partial isometries in such that
In particular, , in that order, are exact matrix units for a unital copy of .
Proof. Suppress the subscript ; every assertion of convergence refers to this sequence. Taking traces in the last two relations of (50.1) gives , since .
Put . The scalar inequality
gives , and hence . Let . First,
The last trace tends to zero because and in . Likewise,
Thus in . Both and are contractions, so
Take the polar decomposition , with
and . In the corner , the inequality for gives
Since , it follows that
. Also
on , the positive operator is zero. Consequently and .
The unused projection is , with . Proposition 13.3 supplies orthogonal equivalent projections with , and a partial isometry with , . Define
The initial supports of are orthogonal, as are their final supports. Thus and . Moreover,
This proves (50.2). Because the final support of is orthogonal to its initial support, ; the remaining matrix-unit identities follow from its two support equations.
The construction divides the unused projection into two equivalent halves. It does not infer equivalence of arbitrary projections from equality of their scalar traces. In particular, if is the normalized center-valued trace, then
This follows from equivalence and additivity, even when is large.
Keeping the new matrix algebra in a relative commutant
Definition 50.2. A unital inclusion with common faithful normal tracial state has the relative matrix property if, for every finite and , there are matrix units of a unital satisfying
Lemma 50.3. Suppose are finite type II algebras with the relative matrix property. If is a unital subalgebra of , the new matrix algebra in (50.6) can be chosen in .
Proof. Let be the matrix units of . On , the trace-preserving expectation onto is the finite average
Matrix multiplication shows that the image commutes with , and the formula fixes . The summands are completely positive maps; , so the average is unital. Cyclicity gives , and the formula is bimodular over its range. It restricts to . Also
For each , apply the relative matrix property to together with all , with tolerance . Denote the resulting matrix units by . Let
and
.
They are respectively positive contractions and contractions. Equation (50.8) makes them -close to the original matrix units. The product estimate
shows that they satisfy (50.1) in .
For clarity, is type II. The usual matrix decomposition identifies with , and with the corner : the corner map is , whose inverse is . A nonzero abelian projection in this corner would be one in .
Apply Lemma 50.1 in . Its exact matrix units converge in to the raw ; the other two units are adjoint and complement. For , perturbing a unit by changes its commutator by at most . For sufficiently large , all four corrected units satisfy (50.6) with the requested .
Two algebras, one infinite tensor factor
Theorem 50.4 — relative tensor absorption. Let be finite type II algebras with common faithful normal tracial state, separable preduals, and the relative matrix property. There are finite tracial algebras and a unital , isomorphic to , for which multiplication gives simultaneous trace-preserving normal isomorphisms
Consequently, as inclusions with their traces,
Proof. Choose -dense sequences in the unit balls of and , written . We construct commuting copies in . Put
Let be (50.7) for , and put . Start with any unital , supplied by the relative matrix property.
For matrix units of , , define the coefficient of by
Then
Indeed, multiplication by on either side of gives . Summing gives . The corner identity
, together with the corner isomorphism in Lemma 50.3, gives . If , then .
After have been chosen, form a finite set containing:
every coefficient in (50.11) of and , for ;
for every , .
Choose by Lemma 50.3, requiring that each of its four matrix units -commute with . This choice makes all the commute.
Convergence to the two complements. On , averaging over is the expectation onto . It is also the restriction of . One can see this directly by writing the matrix units of as tensor products in (50.7). Thus , and (50.8) gives, for ,
If , then for ; at , . Consequently
The sequence is -Cauchy and bounded in operator norm by . Its bounded limit belongs to every , since their bounded balls are -closed. Therefore, with
we have and
If , all its averages belong to , so .
Generation of both algebras. Fix , and let . Replace every coefficient of in (50.11) by its . The resulting element is in , and its distance from is at most
The same replacement for lies in , with the same bound. Since can tend to infinity, each dense element belongs to the corresponding von Neumann algebra. Formally, its vector lies in the closed subspace of that algebra, and the trace-preserving expectation fixes it. Hence
where .
The multiplication maps. The compatible binary matrix union, with its unique matrix traces, is the usual algebraic model of . Lemma 2.1 of the cited uniqueness lesson extends its trace-preserving identification to . This argument does not require the containing algebra to be a factor.
For , cyclicity and its commutation with give
For example, the diagonal pairings are equal because
; their sum is . Off-diagonal pairings vanish after cycling to the other side. Thus for . Multiplication from into is a unital trace-preserving *-homomorphism. The product trace is faithful. Lemma 2.1 extends the map to an injective normal map from whose range is . Its restriction to has range . The definitions of give their relative-commutant descriptions. This proves (50.9).
Finally, by interlacing its binary tensor factors, as in Lemma 2.2(b) of the cited lesson. Apply this isomorphism to the common last factor in (50.9) to obtain the first line of (50.10).
For a general integer , choose equivalent orthogonal projections of trace summing to in , and matrix units connecting them. They give a unital and the exact matrix decomposition
where the corner has its normalized trace. The corner is isomorphic to , by Exercise 3 and its solution in the cited uniqueness lesson. Thus , with normalized traces. Applying this to the same common factor proves the second line of (50.10). The corner theorem is a declared hyperfinite prerequisite; the binary interlacing alone only proves absorption for powers of two.
Figure 50.1. The all lie in and commute exactly with their predecessors. The complements decrease. The finite-stage coefficient count is ; the tail bound is less than , so the reconstruction error is less than . The same last factor occurs in both final multiplication maps. This is a diagram of the proved construction, not a claim that either complement is a factor. Proof locators: Lemma 50.3 and (50.11)–(50.14); reproducible source: relative-absorption.py.
Applying the construction to a Jones core
Use the integer convention of Going up and down the Jones tower, Proposition 4.7. Let be a proper finite-index II₁ inclusion, , and choose its tunnel. Set for , so . Its core pair is
Closures are taken in the inherited tracial representation.
Proposition 50.5. The pair satisfies the hypotheses of Theorem 50.4. In particular it absorbs and every simultaneously, whether or not are factors.
Proof. For fixed , let
Proposition 4.7 gives and . Hence ; each generator lies in one , and is closed. Every element of commutes with .
We need the full tracial size of this tail, rather than merely the distant-commutation relations. The satisfy the Jones adjacent and distant relations with . On an interval , word reduction at its left endpoint is Lemma 11.1, reversed. Its coefficients are in , while
Thus for words in the remaining interval. This recursively determines the trace of every word in the . The canonical path trace has exactly this left-end rule, by Lemma 11.3.
The admissible-index theorem, Theorem 7.2, says that for , or . Use respectively the or model. For any polynomial , the recursion just proved gives equality of the two traces of . Both traces are faithful on the generated algebras. A polynomial vanishes in one model exactly when it vanishes in the other. Substitution is consequently a well-defined trace-preserving *-isomorphism of their algebraic unions. Trace-preserving extension, or the GNS unitary in Proposition 11.2, identifies the von Neumann closures. Theorems 9.6 and 10.5 show that is an infinite-dimensional finite factor, including . It is therefore II₁.
The finite algebras are finite dimensional by finite-index relative-commutant finiteness, Theorem 2.5, and index multiplicativity along the tunnel. Their countable unions imply separable preduals for , even when the ambient has no separability assumption.
They are type II. Here is the type check explicitly. A finite algebra with a nonzero type I part has a nonzero homogeneous central summand for some finite , by the structure theorem for type I algebras, Theorem 10.3 of the projection lesson. A normal unital embedding of the factor remains injective on restriction to any such nonzero central summand: the kernel is a weakly closed ideal of the factor. But contains a unital . Evaluating at any character of its nonzero unital abelian algebra would give a unital representation of on . Its equivalent nonzero diagonal projections would have equal positive ranks summing to , which is impossible. Thus neither nor has a type I summand.
Finally, let be finite and . Increasing trace expectations onto converge to the identity in , because their ranges have dense union. Choose so that
for every . Choose any unital , with matrix units . They commute exactly with , and
They lie in . This proves the relative matrix property. All hypotheses of Theorem 50.4 have now been checked.
The proper-inclusion hypothesis is essential to this argument. At , every Jones projection is , the cup-generated tail is scalar, and (50.16) supplies no .
This proves the core tensor-absorption assertion in Sorin Popa's Classification of amenable subfactors of type II, Section 1.4.4. The shared factor and simultaneous maps in (50.9) make this conclusion explicit. The proposition's embedded-core realization requires transporting the Jones projections, recognizing a new tunnel, and identifying its entire core closure; tensor absorption alone does not establish that conclusion. The actual opposite-model assertion and its entire upper-tower trace and cup compatibility are proved in 50.6–50.8.
For the relative Følner argument in Relative hypertraces and finite Følner projections, the subsequent change of core must also identify the canonical basic constructions and their centers, and prove the change in normalized center-valued trace. Those steps, integer rounding, bounded frames, and the full local/global generating-tunnel equivalence remain separate proof obligations.
Stability of the actual opposite model and its upper tower
Let be II₁ factors of index . Choose any ordinary tunnel and its upward extension , with . Use the original tracial completion
The actual opposite pair is . Its upper tower runs in the decreasing direction of the subscripts:
For , let be the inherited tracial expectation. Keep both cups from 63.6–63.8:
The original implements ; implements . At every step the standard basic-construction trace is . These assertions apply to every integer : the tower starting at has the same cofinal tracial completion , so reindexing 63.6–63.8 changes neither its algebras nor its trace. No identification of the physical opposite trace with a reflected downward trace is made.
Proposition 50.6 — relative matrix approximation in the opposite pair. The actual has the relative matrix property, both algebras are finite type II, and both have separable predual. No separability of the original factors, extremality or amenability is required.
Proof. For , put . These are finite dimensional. The original expectations preserve commutation with , and converge to the identity on in . Consequently . The same argument with gives a countable finite-dimensional exhaustion of . It proves the asserted separability for these model algebras even with a nonseparable ambient factor.
The original cup tail
is a unital II₁ factor. Indeed its Jones relations and the original scalar Markov trace are the canonical path-trace representation of 11.2; the factor argument used in 50.5 applies at every proper admissible index, including four. This also makes type II by the type-I exclusion argument in 50.5: a nonzero homogeneous finite type-I central summand cannot contain a normal unital copy of .
For finite and , choose so for every . Any unital binary matrix algebra in commutes with every . Its matrix units therefore satisfy
This is exactly Definition 50.2.
Theorem 50.7 — one common factor for the full upper opposite tower. There is a unital hyperfinite II₁ factor such that, on putting , multiplication gives trace-preserving normal isomorphisms
There are also compatible trace-preserving normal isomorphisms , for every . For every their precise fixed-element equations are , , and . They intertwine both and and preserve the canonical trace on every positive element of each basic construction. In particular the actual opposite pair simultaneously absorbs the hyperfinite II₁ factor and every finite matrix algebra.
Proof. Apply Theorem 50.4 using 50.6. It supplies in and, with , the multiplication decompositions
Here and below these equalities mean the specified multiplication maps with the product traces. The complements need not be factors.
Every , , belongs to , so commutes with . The basic-construction equalities
therefore extend (50.23) inductively to
For precision, adjoining to has range . Its commutant of is , by 51.3. This identifies it with and proves the entire next decomposition. Trace factorization, faithful product trace and normal extension are the same multiplication argument (50.14); none requires factoriality of .
Identify with its binary tensor model and split its sites into even and odd sets:
Each of the two factors is a copy of . Reindexing all binary sites onto the even sites is a trace-preserving normal isomorphism . Now
These maps have compatible restrictions because the are nested, and they fix every element of each . In particular they fix the original and corrected cups and the densities in (50.24). The choice of half the binary sites is essential: 50.4 does not assert that removing its entire leaves a complement isomorphic to the original pair.
The maps preserve each finite trace and both endpoints of every adjacent inclusion. Uniqueness of trace-preserving conditional expectations gives
The second equality follows from the first and the fixed in (50.19). Since , the entire standard basic-construction identification in 63.8 is preserved. Its canonical trace is on all positive elements; trace preservation gives that same identity on the complement, with no restriction to a finite Jones ideal. This proves the assertion about the entire upper tower. The pair absorption statements also follow directly from 50.4.
Theorem 50.8 — any prescribed finite matrix factor. Let be any unital subalgebra of , . The whole upper tower is normally trace-isomorphic to , with compatible maps fixing the same , . Both expectations and all canonical positive-cone traces are preserved. Multiplication identifies every with .
Proof. First choose a unital in . The normalized corner theorem used in the proof of 50.4 gives a normal trace-preserving isomorphism . Combining it with the identity on each in (50.24) gives the claimed compatible maps for , fixing all cups and densities.
The two unital matrix algebras are unitarily conjugate inside . Indeed their diagonal minimal projections have center-valued trace . The exact finite-algebra comparison in TE16 supplies a partial isometry between their first diagonal projections. If and are the two systems, take , . Then
Thus . Conjugation by preserves every , , and fixes all the cups and densities, since they lie in . Conjugate the compatible maps for by on the source and on the target. Their images are exactly ; all the preceding compatibility and trace conclusions persist. The final multiplication statement is the ordinary unital matrix decomposition, with its normalized product trace.
At index one the opposite endpoints are scalar, so they do not absorb a nontrivial matrix factor or . The proper-index hypothesis is necessary. Theorems 50.7–50.8 prove tensor stability of the actual opposite model, as in Popa, Section 1.4.4, Proposition, printed p.189, and specify its coherent upper-tower form. They do not realize an arbitrary prescribed infinite factor complement, identify a different represented copy with an ordinary ambient core, or establish the general nonextremal physical bicommutant.
Figure 50.2. The top row is the actual upper opposite tower, with subscripts decreasing to the right. The common factor starts in . The lower row uses the odd binary sites as ; the even sites remain in each complement. Equation (50.26) gives one compatible map at every stage, fixing the original cups, their canonical rescalings and densities. Every individual basic-construction trace is . All boxes are schematic; their widths encode no indices or trace masses. Human context: Popa, Section 1.4.4, printed p.189. Editable figure source and finite tensor checks.
Examples and exercises with complete solutions
Example 50.6 — a center survives absorption. Let and , with embedded as and product traces. Binary matrix algebras sufficiently far out in the last factor commute with finite tensor approximants to any given finite set in . approximation proves the relative matrix property. Here one can take , , and . Neither algebra is a factor. The same occurs in both decompositions.
Exercise 50.1 — equal scalar size is insufficient (basic). In with product trace, compare
and . Both have scalar trace . Are they equivalent?
Solution. The normalized center-valued traces are
and .
Equivalence preserves center-valued trace, so . More directly, compression by the central projection kills and leaves a nonzero part of , which an equivalence cannot do. Lemma 50.1 avoids this false scalar comparison by halving the actual residual projection.
Exercise 50.2 — the finite coefficient formula (intermediate). For , verify and show that the four coefficients belong to whenever .
Solution. Substitute the definition in (50.11):
For each , left multiplication of gives , and right multiplication gives the same expression. All terms defining lie in if , because the matrix units do. This proves both claims.
Exercise 50.3 — choose a summable budget (intermediate). Replace by in the construction. What condition on makes the coefficient reconstruction tend to zero? Give the exact bound at stage .
Solution. The averaging tail is bounded by
There are coefficients, so the reconstruction bound is
It tends to zero exactly when . At , this bound is constant, so this argument gives no convergence. For , the exact bound is .
Exercise 50.4 — locating a negative cup (intermediate). Check the locations of and in (50.16), and determine why they commute with . What changes at index one?
Solution. Proposition 4.7 puts in , commuting with . It puts in , commuting with . Hence both are in . Since , every element of commutes with all of , so it commutes with both cups and their tail closure. At index one their trace is one, and faithfulness makes both projections the identity. The tail is then scalar.
Exercise 50.5 — the same isomorphism for both members (advanced). Explain why individual isomorphisms and would not suffice for (50.10). Prove absorption of using (50.9).
Solution. Individual isomorphisms need not carry the specified embedded copy of into the specified tensor copy of inside . Equation (50.9) instead presents that inclusion as
Choose a unital . Its first diagonal corner is a hyperfinite II₁ factor isomorphic to , giving a trace-preserving isomorphism
.
Then maps the larger tensor product onto and restricts to on the smaller one. Compose with the simultaneous multiplication maps. This is the required isomorphism of inclusions.
Exercise 50.6 — the opposite finite tests
Let and . Show that . If a binary matrix unit is chosen as in (50.20), prove . Explain why this argument adds no separability hypothesis on .
Solution. For each unitary , bimodularity gives . Hence its value is in the asserted finite commutant. Every generator of commutes with , so . The triangle inequality and give the estimate. The countable finite-dimensional commutant union has closure , and the corresponding union for has closure ; these model algebras have separable preduals regardless of the ambient cardinality. Thus 50.4 is applied only where its separability hypothesis has actually been proved.
Exercise 50.7 — keep half the common factor
Suppose the multiplication decomposition from 50.4 is . Why does it not justify ? Give the explicit replacement that produces isomorphic complements while fixing every .
Solution. A tensor complement of an infinite factor can be finite dimensional; the original algebra is recovered only after tensoring it with . Split and remove . Then . Reindexing all binary sites onto the even sites defines the single normal trace-preserving . The maps agree on every preceding stage and fix , and , since these are in the first tensor leg. They preserve both expectations by (50.27); no original cup is replaced by the corrected one.
Exercise 50.8 — the prescribed matrix unitary
Verify that (50.28) is unitary and carries to . Why does its use preserve the entire upper opposite tower and both cup conventions even with nonfactor endpoints?
Solution. Orthogonality of the matrix units gives
The same multiplication gives . Since for every , it normalizes every such . All , , belong to , which commutes with , so they are fixed. The partial isometry used here exists by equality of the actual center-valued traces ; scalar trace equality alone in a nonfactor algebra would not suffice.
Authored by GPT-6.1 Sol (OpenAI), Ultra reasoning, October 2026. Original exposition released under CC0 1.0.