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Continuous outer actions of locally compact groups

Written by GPT-6.1 Sol (OpenAI), Ultra. Original programme exposition: CC0-1.0 to the extent of rights held. Human-source notices retain their separate terms.

A displaced vector in the regular representation, copied into infinitely many orthogonal summands, gives a continuous outer action on the tracial CAR factor. The copies prevent a Hilbert–Schmidt perturbation of the identity; the complete complex CAR criterion turns that obstruction into outerness.

Here GG is a locally compact Hausdorff group with a countable base. The full CO0–5 inputs supply compact cutoffs, the exact complete Haar-measure route, the entire regular Hilbert space, the completed tracial CAR algebra, full normal extension and point-predual continuity, the whole Hilbert–Schmidt innerness proof and topology transport. The target is every separable AFD factor of type II1\mathrm{II}_1. Neither amenability nor connectedness nor unimodularity is assumed.

Start with a genuinely displaced vector

CO1's complete compact-content/Borel construction gives left Haar measure mm, finite on compact sets and positive on nonempty open sets. CO0's compact-neighborhood proof and the countable base give a countable relatively compact open cover, hence sigma-finiteness. Set H0=L2(G,m)H_0=L^2(G,m), with pairing ⟨f,h⟩=∫f‾h dm\langle f,h\rangle=\int\overline f h\,dm, and define

(λ(g)f)(t)=f(g−1t).(1)(\lambda(g)f)(t)=f(g^{-1}t). \tag{1}

Left invariance proves unitarity on indicators, simple functions and their whole Hilbert completion. Substitution gives the representation law.

Lemma 1.1. The Hilbert space H0H_0 is separable, and λ\lambda is strongly continuous and faithful.

Proof. CO2 gives the complete L2L^2 measure and convergence arguments. On each finite-measure cover member, approximate a Borel set from within by a compact set and from outside by an open set. A finite union of countable-base members fits between them and approximates its indicator in L2L^2. Rational complex combinations of these countably many indicators are dense, by simple approximation and truncation to the cover. Thus H0H_0 is separable. Completion of the measure introduces no new L2L^2 classes: its functions have the Borel representatives proved in CO1.

CO0's compactly supported cutoff gives Cc(G)C_c(G)-density by the indicator estimate in CO2.1. For f∈Cc(G)f\in C_c(G), and gg near ee in a compact neighborhood CC, all translated supports lie in the compact set Csupp⁡fC\operatorname{supp}f. Joint continuity and a finite product-neighborhood cover give uniform convergence of f(g−1t)−f(t)f(g^{-1}t)-f(t) to zero on that set. Its finite measure gives L2L^2 convergence. The common unitary bound and CcC_c-density prove convergence on every vector, for parameter nets. The group law gives continuity at every parameter.

For g≠eg\ne e, choose disjoint neighborhoods of ee and gg, and then a nonempty relatively compact open VV with

V∩gV=∅.(2)V\cap gV=\varnothing. \tag{2}

Continuity of left multiplication and the compact-neighborhood shrinking proof permit this choice. Haar positivity and compact finiteness give 0<m(V)<∞0<m(V)<\infty. Therefore

ξ=m(V)−1/21V,∥λ(g)ξ−ξ∥2=2.(3)\xi=m(V)^{-1/2}1_V,\qquad \|\lambda(g)\xi-\xi\|^2=2. \tag{3}

The two supports are disjoint and their measures agree. This proves faithfulness. All claims use the full constructed measure and Hilbert space. □\square

Exercise 1. Verify the law for (1) and the absence of a modular multiplier.

Solution. At f∈L2f\in L^2,

(λ(g)λ(h)f)(t)=f(h−1g−1t)=f((gh)−1t).(\lambda(g)\lambda(h)f)(t) =f(h^{-1}g^{-1}t)=f((gh)^{-1}t).

The formulas hold on Borel representatives and then on their classes. Left translation preserves the chosen left Haar measure, so its change of variables preserves the whole L2L^2 norm. This uses left translation, not right translation against left Haar measure; the latter would need the modular correction.

Exercise 5. For G=RG=\mathbb R, find an explicit displaced unit vector for each nonzero ss.

Solution. Lebesgue measure is left Haar measure by its complete interval outer-measure construction in the linked tools lesson. Take V=(0,r)V=(0,r) with 0<r<∣s∣0<r<|s|. Its translate s+Vs+V is disjoint, and ξ=r−1/21V\xi=r^{-1/2}1_V has norm one. For (λ(s)f)(t)=f(t−s)(\lambda(s)f)(t)=f(t-s), both squared norms are one and the mixed inner product is zero, giving distance 2\sqrt2. The infinitely repeated representation below therefore yields a continuous real action with every nonzero time outer.

Repeat the displacement while retaining continuity

Let

K=H0⊗ℓ2(N)=⨁n≥1H0,U(g)=λ(g)⊗1.(4)K=H_0\otimes\ell^2(\mathbb N)=\bigoplus_{n\ge1}H_0,\qquad U(g)=\lambda(g)\otimes1. \tag{4}

The equality is the complete Hilbert tensor/direct-sum identification on elementary coordinates. It is separable, and it is infinite dimensional even when GG is finite or trivial: H0≠0H_0\ne0, and a fixed nonzero vector in its separate summands gives infinitely many orthogonal vectors.

Lemma 2.1. For every g≠eg\ne e,

U(g)−1∉L2(K).(5)U(g)-1\notin\mathcal L^2(K). \tag{5}

In fact U(g)−1U(g)-1 is not compact.

Proof. At g≠eg\ne e, choose ξ\xi as in (3). The vectors ηn=ξ⊗en\eta_n=\xi\otimes e_n are orthonormal and

∥(U(g)−1)ηn∥2=2.(6)\|(U(g)-1)\eta_n\|^2=2. \tag{6}

Extend them to an orthonormal basis. Basis independence and the whole square-sum Hilbert–Schmidt construction in CO4 show that these infinitely many contributions already make the sum infinite. Their images lie in distinct summands, are orthogonal and have norm 2\sqrt2. They have no convergent subsequence, proving noncompactness. □\square

The representation law holds on the complete direct sum. Strong continuity follows by retaining a finite prefix of any vector and estimating the remaining tail by the common unitary bound, as the next full solution shows. More generally any faithful strongly continuous representation on a nonzero separable space has a vector with some nonzero displacement cc; repeating it gives infinitely many squared contributions c2c^2.

Exercise 4. Prove whole strong continuity of (4), with an explicit tail estimate.

Solution. Write η=(ηn)\eta=(\eta_n). Then

∥(U(g)−U(g0))η∥2=∑n∥(λ(g)−λ(g0))ηn∥2.\|(U(g)-U(g_0))\eta\|^2 =\sum_n\|(\lambda(g)-\lambda(g_0))\eta_n\|^2.

Given ε>0\varepsilon>0, choose NN with 4∑n>N∥ηn∥2<ε2/24\sum_{n>N}\|\eta_n\|^2<\varepsilon^2/2. Strong continuity on the finitely many prefix vectors makes their sum less than ε2/2\varepsilon^2/2 in one parameter neighborhood. Each tail difference has norm at most 2∥ηn∥2\|\eta_n\|, so the whole squared norm is less than ε2\varepsilon^2. This works for every vector and for nets.

Exercise 3. Prove that a nonzero bounded TT has a non-Hilbert–Schmidt, noncompact repetition T⊗1ℓ2T\otimes1_{\ell^2}.

Solution. Choose a unit ξ\xi with ∥Tξ∥=c>0\|T\xi\|=c>0. The orthonormal ξ⊗en\xi\otimes e_n's have images in different summands, all of norm cc. An orthonormal basis containing them contributes ∑nc2=∞\sum_n c^2=\infty to the Hilbert–Schmidt sum. The mutually orthogonal images stay at distance 2c\sqrt2c from each other, so no subsequence converges. This also proves noncompactness and applies in particular to T=λ(g)−1T=\lambda(g)-1.

Exercise 2. Compute the Hilbert–Schmidt square norm for a finite group's nonidentity regular permutation, and on NN copies.

Solution. Use counting measure and its orthonormal δh\delta_h's. If g≠eg\ne e, left multiplication fixes none of them: gh=hgh=h would imply g=eg=e. Thus λ(g)δh\lambda(g)\delta_h and δh\delta_h are distinct orthonormal vectors, with squared difference two. The whole finite basis gives

∥λ(g)−1∥HS2=2∣G∣.\|\lambda(g)-1\|_{\mathrm{HS}}^2=2|G|.

On NN summands it is 2N∣G∣2N|G|. Infinitely many summands give divergence, while one finite summand remains a Hilbert–Schmidt perturbation.

The tracial CAR action on the entire factor

CO3 builds the norm-complete CAR algebra on the actual KK, with conjugate-linear annihilation a(f)a(f) and ∥a(f)∥=∥f∥\|a(f)\|=\|f\|. Its trace representation is the complete tracial matrix product RKR_K, a separable AFD II1\mathrm{II}_1 factor. Its finite CAR algebras and arbitrary overlapping mode maps are proved explicitly. Define

βg(a(f))=a(U(g)f).(7)\beta_g(a(f))=a(U(g)f). \tag{7}

CO3 extends this prescription to a trace-preserving automorphism of the whole norm algebra, then normally to the entire RKR_K, with full normal inverse. Its vector-series argument proves point-predual norm continuity for every normal functional. CO4 proves the entire complex-linear factor criterion: βg\beta_g is inner exactly when U(g)−1U(g)-1 is Hilbert–Schmidt, using the complete tracial product criterion, bounded logarithm, dyadic diagonal perturbation and normal group law.

Theorem 3.1. The map

β:G⟶Aut⁡(RK)(8)\beta:G\longrightarrow\operatorname{Aut}(R_K) \tag{8}

is a continuous injective homomorphism, preserves the normalized trace, and satisfies

βg is inner⟺g=e.(9)\beta_g\text{ is inner}\quad\Longleftrightarrow\quad g=e. \tag{9}

For any separable AFD factor R0R_0 of type II1\mathrm{II}_1, transporting (8) along a normal isomorphism gives such an action on R0R_0.

Proof. The whole CAR construction and normal extension just described give the trace-preserving normal automorphisms. Their generator law gives βgβh=βgh\beta_g\beta_h=\beta_{gh} on the norm algebra and then normally on all RKR_K. Strong continuity of (4), composed with CO3.4's whole vector-pair-series estimate, proves point-predual norm continuity.

By CO4's full factor criterion and Lemma 2.1, every g≠eg\ne e gives an outer automorphism; g=eg=e gives the identity. If βg=βh\beta_g=\beta_h, the homomorphism law makes βh−1g\beta_{h^{-1}g} the identity and hence inner, so g=hg=h. This proves injectivity.

AF5's complete separable AFD II1\mathrm{II}_1 uniqueness proof supplies a normal isomorphism θ:RK→R0\theta:R_K\to R_0, with whole normal inverse. Put

γg=θβgθ−1.(10)\gamma_g=\theta\beta_g\theta^{-1}. \tag{10}

CO5's predual isometries prove both directions of the topology homeomorphism. The same normal identification transports the normalized trace, by the full canonical trace uniqueness proof. An implementing unitary is transported or pulled back by θ\theta, so innerness and outerness are preserved. Thus every stated conclusion holds on the whole R0R_0. □\square

Exercise 7. Verify the full point-predual topology and outerness transport in (10).

Solution. For ρ∈(R0)∗\rho\in(R_0)_* and β,β′∈Aut⁡(RK)\beta,\beta'\in\operatorname{Aut}(R_K),

∥ρθβθ−1−ρθβ′θ−1∥=∥(ρθ)β−(ρθ)β′∥.\|\rho\theta\beta\theta^{-1}-\rho\theta\beta'\theta^{-1}\| =\|(\rho\theta)\beta-(\rho\theta)\beta'\|.

Precomposition by the normally onto isomorphism θ−1\theta^{-1} is an isometry on the whole unit-ball functional norm. These identities for every ρ\rho give continuity; those for θ−1\theta^{-1} give the inverse continuity. If v∈R0v\in R_0 implements the transported map, then the unitary θ−1(v)∈RK\theta^{-1}(v)\in R_K implements the original map. Pushing an original implementer forward proves the converse. Thus outerness is preserved in both directions.

Exercise 6. Does a faithful one-particle representation by itself guarantee an outer CAR action?

Solution. A nontrivial finite group has its faithful finite-dimensional regular representation. Its differences from the identity have finite rank and are Hilbert–Schmidt. After adjoining an infinite-dimensional trivial summand, the differences still have finite rank; the full complex-linear criterion makes every resulting CAR automorphism inner, even though the representation is faithful and its Hilbert space is now infinite dimensional. Repeating the nontrivial representation creates infinitely many displaced modes. Merely adding unused modes does not do so.

Exercise 8. Treat the trivial group and the resulting factor type.

Solution. For G={e}G=\{e\}, H0H_0 is one dimensional. Its countable repetition K=H0⊗ℓ2K=H_0\otimes\ell^2 is separable infinite dimensional, and CO3's entire tracial product proof makes RKR_K a factor of type II1\mathrm{II}_1. The only element acts as the identity. The group map is injective and its nonidentity-outerness statement is vacuous. Without repetition the one-mode CAR algebra would instead be M2M_2. This endpoint is part of the same construction.

Countability and the exact free comparisons

The second-countable hypothesis is retained throughout. Countable density by itself does not supply it. For instance, if a compact group acts through a continuous injective map into the Hausdorff Polish Aut⁡(RK)\operatorname{Aut}(R_K), the map is a homeomorphism onto its image: compact closed sets have compact, hence closed, images. Its domain is therefore metrizable, as a subspace of that metric group. The complete automorphism-topology proof is in the central-sequence foundations. A compact nonmetrizable group cannot be covered by silently replacing second countability with separability.

Robert J. Blattner, Automorphic group representations, Section 6, printed pp.673–675, Definition 3 and the full corollary, compares the repeated regular representation and explicitly assumes second countability. It uses real Clifford generators and point-weak continuity. CO3–4 supply the complete complex tracial CAR argument and whole point-predual norm continuity here.

A. L. Carey, Inner automorphisms of hyperfinite factors and Bogoliubov transformations, Proposition 3.1 and the preceding paragraph, printed p.148, compares repeated regular representations with a displayed type III parameter 0<λ<1/20<\lambda<1/2. That proposition is not used to infer the current tracial factor type. CO3 constructs the actual half-trace matrix factor; CO4 proves its complex-linear criterion and explains the excluded negative real-Clifford branch.

D. H. Fremlin's author-supplied 2013 §441C(b–f), §441E is the compact-cover Haar method comparison. The linked programme content proof supplies every Borel-conversion step, while CO0–2 supply compact cutoffs, whole L2L^2 approximation and regular-representation continuity. Human-source terms are retained; free access is not treated as a grant to relabel human expression.