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Measure and Hilbert space tools for Haar integration

Written by GPT-6.1 Sol (OpenAI), Ultra reasoning effort, October 2026. Self-checked by the writing AI, GPT-6.1 Sol. Original exposition is public domain (CC0).

Bounded prerequisite selection (October 2026). This companion selects original lines 1–72, preserving the header and full Carathéodory, integral construction, continuity from below, monotone convergence, Fatou and dominated convergence proofs. Later Hilbert-space, duality and calculus results mentioned in the original introduction and bibliography are source context outside this selection. These selected measure proofs supply the full measure-theoretic input used by the positive Riesz construction. The selected source prose and mathematics are unchanged apart from link destinations and line-ending normalization. Selection and link repair: GPT-6.1 Sol (OpenAI), Ultra reasoning effort, for the AN-01 course project.

Haar integration needs convergence theorems even when the group has uncountably many open components. It also needs a precise meaning for a tensor product of Hilbert spaces. This lesson proves the measure results used in the next lesson and explains which parts require countability. The finite-measure arguments are deliberately separated from the arguments valid on every measure space.

The earlier programme lesson Hilbert spaces and compact operators, Theorems 2.1–2.3, 4.1 and 8.1, proves orthogonal projection, representation of a bounded Hilbert-space functional, orthonormal bases and the Hilbert tensor product. Those complete proofs are the Hilbert-space prerequisites below. Elementary set theory, including the axiom of choice, is assumed. No topology is needed until the following Haar lesson. The core course Measure and Integration uses Fremlin’s human text. The core Real Analysis I and Real Analysis II use J. Lebl’s open Basic Analysis. Our Lemma 6.1 supplies the one-variable integral identities used here. Basic references for measure theory are [Fremlin] and [Lebesgue].

1. From an outer measure to a measure

A sigma-algebra on a set is a family containing and closed under complements and countable unions. A measure on it is a function into taking the empty set to zero and countably additive on disjoint sets. An outer measure is defined on every subset of , is zero at the empty set, is monotone, and satisfies

Theorem 1.1 (Carathéodory). The sets satisfying form a sigma-algebra. The restriction of to it is a complete measure. To verify (1.1) it suffices to prove its greater-than-or-equal inequality for with finite outer measure.

Proof. The other inequality is subadditivity; when , the greater-than-or-equal inequality is automatic. Complements preserve the condition. If satisfy it, split first by , and then split by . The sum of the first two resulting terms is at least , by subadditivity. This proves the condition for ; differences and finite intersections follow.

Let be disjoint sets satisfying the condition, and put . Repeated finite splitting gives Let increase. Subadditivity gives , so satisfies the condition. An arbitrary countable union is reduced to this case by replacing with . Thus the family is a sigma-algebra. Taking in the finite-splitting inequality proves countable additivity on the disjoint , together with subadditivity. If has outer measure zero, every subset of satisfies (1.1): monotonicity makes the first term zero, while monotonicity and subadditivity force the second term to equal . This also proves completeness.

Example. Assign to a subset of the real line the infimum of the sums of lengths of countable open interval covers. This is an outer measure: combine covers with errors to prove subadditivity. Splitting every covering interval at a fixed point splits its total length between the two half-lines; enlarge the split intervals by errors whose sum is arbitrarily small. This gives the reverse Carathéodory inequality for each half-line. Half-lines generate the Borel sigma-algebra, so Theorem 1.1 makes every Borel set measurable.

The measure of is . An enlarged interval gives the upper bound. For any countable open cover of , compactness selects a finite subcover. The sum of its interval lengths is at least : arrange its endpoints in order, and each successive subinterval of is covered by at least one member. Summing lengths proves the lower bound. Singletons have measure zero, so the same length formula holds for open and half-open bounded intervals. Translating or dilating interval covers shows directly that and for , using the inverse operation for the reverse inequalities. The resulting Borel Lebesgue measure, or its completion, is therefore translation invariant. The next lesson instead constructs an outer measure using continuous functions on an arbitrary LCH space.

2. Integration and convergence without countability assumptions

Fix a measure space . A measurable real function is one for which for every real . Countable suprema and infima are measurable: use , and negate for infima. Limits are measurable because . Complex functions are measurable when their real and imaginary parts are.

For a nonnegative simple function , with disjoint measurable and , define , with . Refining two partitions proves independence of the presentation, monotonicity, and additivity for simple functions. For measurable , define There are increasing simple : truncate at and round down to multiples of . The truncation bounds and the refining dyadic grids ensure monotonicity.

Countable additivity implies continuity from below: if , write as the disjoint union of . Then . If and , apply this to to obtain continuity from above.

Theorem 2.1 (Monotone convergence). If almost everywhere, then .

Proof. Discard one measurable null set to obtain pointwise inequalities; changing values there changes none of the integrals. Monotonicity gives . For simple and , the sets increase and cover . Consequently continuity from below on the finitely many level sets of gives . Since , the limit of their integrals is at least . Let and then take the supremum over . The same argument works when .

Applying this to increasing simple approximations of proves . Applying it to partial sums proves These identities justify defining the integral of an integrable real function as , and then treating complex functions by real and imaginary parts. Here integrable means . Linearity follows from nonnegative additivity by moving all negative parts to the opposite side of the desired equality. Choosing a phase so that is nonnegative real gives .

Theorem 2.2 (Fatou and dominated convergence). For measurable , If complex measurable almost everywhere and almost everywhere for one integrable , then is integrable and . In particular .

Proof. The functions increase to the liminf, and . Monotone convergence proves Fatou. For the second assertion, almost everywhere. Fatou applied to the nonnegative functions , whose limit is , gives All integrals here are finite, so the limsup is zero. The integral inequality proved above gives the last assertion.

Example. On an uncountable set with counting measure, an integrable function has countable support: for each positive integer , only finitely many points can have . Nevertheless the whole space is not sigma-finite. Theorems 2.1 and 2.2 remain valid. A later interchange of integrals will need a separate theorem; convergence alone does not supply it.

Original source bibliography, retained

References

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