Paragraf

Algoritma kompresi JPEG menggunakan Transformasi Fourier Diskret, yang didefinisikan menggunakan basis \(\bcal\) dengan vektor-vektor basis
\begin{equation*} \begin{aligned} \vvec_0 = \left[\begin{array}{c} \cos\left(\frac{(2\cdot0+1)\cdot0\pi}{16}\right) \\ \cos\left(\frac{(2\cdot1+1)\cdot0\pi}{16}\right) \\ \cos\left(\frac{(2\cdot2+1)\cdot0\pi}{16}\right) \\ \vdots \\ \cos\left(\frac{(2\cdot7+1)\cdot0\pi}{16}\right) \\ \end{array}\right], \amp \vvec_1 = \left[\begin{array}{c} \cos\left(\frac{(2\cdot0+1)\cdot1\pi}{16}\right) \\ \cos\left(\frac{(2\cdot1+1)\cdot1\pi}{16}\right) \\ \cos\left(\frac{(2\cdot2+1)\cdot1\pi}{16}\right) \\ \vdots \\ \cos\left(\frac{(2\cdot7+1)\cdot1\pi}{16}\right) \\ \end{array}\right], \\ \\ \ldots, \vvec_6 = \left[\begin{array}{c} \cos\left(\frac{(2\cdot0+1)\cdot6\pi}{16}\right) \\ \cos\left(\frac{(2\cdot1+1)\cdot6\pi}{16}\right) \\ \cos\left(\frac{(2\cdot2+1)\cdot6\pi}{16}\right) \\ \vdots \\ \cos\left(\frac{(2\cdot7+1)\cdot6\pi}{16}\right) \\ \end{array}\right], \amp \vvec_7 = \left[\begin{array}{c} \cos\left(\frac{(2\cdot0+1)\cdot7\pi}{16}\right) \\ \cos\left(\frac{(2\cdot1+1)\cdot7\pi}{16}\right) \\ \cos\left(\frac{(2\cdot2+1)\cdot7\pi}{16}\right) \\ \vdots \\ \cos\left(\frac{(2\cdot7+1)\cdot7\pi}{16}\right) \\ \end{array}\right]\text{.} \\ \end{aligned} \end{equation*}
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