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\begin{document}

\ReaderArmAliases{\ReaderOriginalAnchorStart{doubling-a-boundary-problem-and-computing-its-index}\ReaderOriginalAnchorEnd}
\section{Doubling a boundary problem and computing its
index}\label{doubling-a-boundary-problem-and-computing-its-index}

A first-order elliptic boundary problem can be turned into an operator
on a closed doubled manifold. The construction has three parts that must
agree exactly: the reflected half must carry the complementary stable
modes, the boundary coupling must stay elliptic while separate boundary
conditions become matching traces, and the resulting mixed operator must
be approximated in operator norm before its continuous symbol can
compute the index.

This lesson proves all three parts. It also resolves a possible
factor-of-two ambiguity: the geometric double built here has a
zero-index complementary half, so its index equals the boundary index. A
one-half formula belongs to a different doubled datum whose
complementary half has the same index as the original problem.

The named prerequisites are \href{stable-boundary-models.pdf}{Stable
modes and the algebra of boundary data},
\href{generalized-collar-fredholm.pdf}{Fredholm boundary problems with
first-order Calderón defects}, \href{fredholm-stability.pdf}{Finite
defects under perturbation}, and
\href{global-elliptic-symbol-index.pdf}{Symbols, finite defects, and the
index on a closed manifold}. We use \(D_t=-i\partial_t\), inward collar
coordinates, and Hermitian inner products linear in the first entry.
Matrix factors retain their displayed order.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-001}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-001}\label{AN03-SDI-001}\endgroup\ReaderOriginalAnchorStart{1-the-split-first-order-model}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{1-the-split-first-order-model}\label{1-the-split-first-order-model}\endgroup\ReaderOriginalAnchorStart{the-split-first-order-model}\ReaderOriginalAnchorEnd}
\subsection{1. The split first-order
model}\label{the-split-first-order-model}

Let \(X\) be compact with boundary \(Y\). Suppose

\[
 E|_Y=E^+\oplus E^-
 \tag{DI1}
\]

is orthogonal for a chosen Hermitian metric. Choose a product density
and product metric in a collar \(Y\times[0,\delta)_t\). Let
\(\phi\in C_c^\infty([0,\delta))\) be real, \(0\leq\phi\leq1\), and
\(\phi=1\) near \(t=0\). Take
\(\Lambda^\pm\in\Psi_{\mathrm{phg}}^1(Y;E^\pm)\) with positive scalar
real principal symbols \(\lambda^\pm(y,\eta)I_{E^\pm}\), and take an
interior operator \(\Lambda\in\Psi_{\mathrm{phg}}^1(X^\circ;E)\) whose
principal symbol \(\lambda(x,\xi)I_E\) is positive for every
\(\xi\ne0\). Extend \(\Lambda^\pm\) constantly in \(t\) where
\(\phi=1\), and put

\[
 \begin{aligned}
 P^bu&=\phi
 \begin{pmatrix}
  D_t+i\Lambda^+&0\\
  0&-D_t+i\Lambda^-
 \end{pmatrix}
 \binom{u^+}{u^-},\\
 P^iu&=i(1-\phi)\Lambda(1-\phi)u,\qquad
 P=P^b+P^i,\qquad Bu=\gamma_0u^-.
 \end{aligned}
 \tag{DI2}
\]

In the collar-transition region the principal symbol is

\[
 p(y,t,\eta,\tau)=
 \phi(t)
 \begin{pmatrix}
  \tau+i\lambda^+(y,\eta)&0\\
  0&-\tau+i\lambda^-(y,\eta)
 \end{pmatrix}
 +i(1-\phi(t))^2\lambda(y,t,\eta,\tau)I_E.
 \tag{DI3}
\]

If \(0<\phi<1\), the imaginary part of each diagonal scalar is positive
at every nonzero covector. Where \(\phi=1\), a nonzero tangential
covector gives a positive imaginary part and a nonzero pure normal
covector gives the real entries \(\pm\tau\). Where \(\phi=0\), the last
term is invertible. Thus \(P\) is elliptic.

Freeze at \((y,\eta)\in T^*Y\setminus0\). The two normal equations and
their solutions are

\[
 \begin{array}{lll}
 (D_t+i\lambda^+)v^+=0,
 &v^+(t)=e^{\lambda^+t}v^+(0),
 &v^+\text{ bounded}\Longleftrightarrow v^+(0)=0,\\[1mm]
 (-D_t+i\lambda^-)v^-=0,
 &v^-(t)=e^{-\lambda^-t}v^-(0),
 &v^-\text{ bounded for every }v^-(0).
 \end{array}
 \tag{DI4}
\]

Hence the stable Cauchy space is exactly \(E^-_y\), and the principal
boundary map \(v\mapsto v^-(0)\) is its identity. The generalized
interior and boundary symbols are elliptic.
\href{generalized-collar-fredholm.pdf}{Fredholm boundary problems with
first-order Calderón defects} therefore makes

\[
 (P,B)_s:\bar H_s(X^\circ;E)\longrightarrow
 \bar H_{s-1}(X^\circ;E)\oplus H^{s-1/2}(Y;E^-)
 \tag{DI5}
\]

Fredholm for every real \(s\geq1\).

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-002}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-002}\label{AN03-SDI-002}\endgroup\ReaderOriginalAnchorStart{2-the-boundary-signs-and-the-shifted-kernel}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{2-the-boundary-signs-and-the-shifted-kernel}\label{2-the-boundary-signs-and-the-shifted-kernel}\endgroup\ReaderOriginalAnchorStart{the-boundary-signs-and-the-shifted-kernel}\ReaderOriginalAnchorEnd}
\subsection{2. The boundary signs and the shifted
kernel}\label{the-boundary-signs-and-the-shifted-kernel}

For a compactly supported smooth scalar or vector function \(w\) in the
collar, integration by parts with the stated inner-product convention
gives the exact signs

\[
 \begin{aligned}
 2\operatorname{Im}(\phi D_tw,w)_X
   &=\|\gamma_0w\|_Y^2+\int_X\phi'(t)|w|^2,\\
 2\operatorname{Im}(-\phi D_tw,w)_X
   &=-\|\gamma_0w\|_Y^2-\int_X\phi'(t)|w|^2.
 \end{aligned}
 \tag{DI6}
\]

Indeed, the first difference from its complex conjugate is
\(-i\int\phi\partial_t|w|^2\), and the endpoint at \(t=0\) has the
displayed positive sign. The second identity is its negative.

The scalar positive principal symbols of \(\Lambda^\pm\) and \(\Lambda\)
give the matrix Gårding lower bounds for the real parts of their
quadratic forms. Derivatives of \(\phi\), nonsymmetric lower-order
terms, and the bounded collar patching terms contribute at most
\(C\|u\|_X^2\). Combining these facts with (DI6) gives

\[
 2\operatorname{Im}(Pu,u)_X
 \geq \|\gamma_0u^+\|_Y^2-
       \|\gamma_0u^-\|_Y^2-C\|u\|_X^2.
 \tag{DI7}
\]

For \(T>C/2\), set \(P_T=P+iT I_E\). If \(P_Tu=0\) and \(Bu=0\), then

\[
 0=2\operatorname{Im}(P_Tu,u)_X
 \geq\|\gamma_0u^+\|_Y^2+(2T-C)\|u\|_X^2.
 \tag{DI8}
\]

Thus \(u=0\). Elliptic regularity from
\href{generalized-collar-fredholm.pdf}{Fredholm boundary problems with
first-order Calderón defects} first makes every weak kernel element
smooth, so the calculation applies to the full kernel of (DI5).

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\subsection{3. The adjoint boundary relation and the shifted
cokernel}\label{the-adjoint-boundary-relation-and-the-shifted-cokernel}

Take the base realization \(s=1\). A pair \((v,h)\) in the annihilator
of the range of \((P_T,B)_1\) is smooth by the dual regularity theorem
in \href{generalized-collar-fredholm.pdf}{Fredholm boundary problems with
first-order Calderón defects}. The leading normal terms give Green's
identity

\[
 (Pu,v)_X-(u,P^*v)_X
 =i(\gamma_0u^+,\gamma_0v^+)_Y
  -i(\gamma_0u^-,\gamma_0v^-)_Y.
 \tag{DI9}
\]

The annihilation equation is therefore

\[
 0=(u,(P^*-iT)v)_X
   +i(\gamma_0u^+,\gamma_0v^+)_Y
   -i(\gamma_0u^-,\gamma_0v^-)_Y
   +(\gamma_0u^-,h)_Y.
 \tag{DI10}
\]

Interior tests and arbitrary boundary traces give, with no change of the
conjugate-linear slot,

\[
 (P^*-iT)v=0,\qquad
 \gamma_0v^+=0,\qquad h=-i\gamma_0v^-.
 \tag{DI11}
\]

Put \(Q=-P^*\). Exchange the names of the two orthogonal summands:

\[
 E_Q^+=E^-,\qquad E_Q^-=E^+.
 \tag{DI12}
\]

The full differentiated-cutoff terms are computed below in (DA3)--(DA5).
The collar principal part of \(Q\), written in the order
\(E_Q^+\oplus E_Q^-\), is

\[
 \begin{pmatrix}
  D_t+i(\Lambda^-)^*&0\\
 0&-D_t+i(\Lambda^+)^*
 \end{pmatrix},\qquad
 B_Qv=\gamma_0v^+=\gamma_0v_Q^-.
 \tag{DI13}
\]

Multiplying the first equation in (DI11) by \(-1\) gives \((Q+iT)v=0\),
while \(B_Qv=0\). The estimate (DI8), with the same sufficiently large
\(T\) after enlarging \(C\) once, gives \(v=0\), and then \(h=0\). Thus
\((P_T,B)_1\) is bijective. The path

\[
 (P+i rT I_E,B),\qquad 0\leq r\leq1,
 \tag{DI14}
\]

keeps both principal symbols fixed and stays Fredholm. Its index is
constant, so \(\operatorname{ind}(P,B)_1=0\).
\href{generalized-collar-fredholm.pdf}{Fredholm boundary problems with
first-order Calderón defects} identifies the same smooth kernel and
adjoint obstruction spaces at every \(s\geq1\). Consequently

\[
 \boxed{\operatorname{ind}(P,B)_s=0\quad(s\geq1).}
 \tag{DI15}
\]

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-ADJOINT-001}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-ADJOINT-001}\label{AN03-SDI-ADJOINT-001}\endgroup\ReaderOriginalAnchorStart{the-full-positivity-remainder-and-adjoint-coefficients}\ReaderOriginalAnchorEnd}
\subsubsection{The full positivity remainder and adjoint
coefficients}\label{the-full-positivity-remainder-and-adjoint-coefficients}

Here is a direct proof of the lower bounds used in (DI7), with their
actual lower-order operators retained. If \(A\) is any of \(\Lambda^+\),
\(\Lambda^-\), or the interior \(\Lambda\), its principal symbol is
\(\lambda_A I\), with \(\lambda_A>0\) off the zero section. Quantize the
degree-one-half symbol \(\sqrt{\lambda_A}I\) to an operator \(R_A\). Use
the full bundle composition and adjoint formulas in
\href{euclidean-symbol-calculus.pdf}{Symbols, operators and Sobolev
scales} and \href{geometric-microlocal-calculus.pdf}{Detecting regularity
without choosing coordinates}. Their principal product is exactly
\(\lambda_A I\). Hence

\[
 H_A=\frac{A+A^*}{2}-R_A^*R_A\in\Psi^0,
 \qquad
 \operatorname{Re}(Aw,w)=\|R_Aw\|_2^2+(H_Aw,w),
 \qquad C_A=\|H_A\|_{L^2\to L^2}.
 \tag{DA1}
\]

The principal symbol comparison proves the order-zero claim; the linked
order-zero mapping theorem makes \(C_A\) finite. The formula retains the
entire lower-order operator \(H_A\), rather than replacing \(A\) by its
positive principal symbol. It gives
\(\operatorname{Re}(Aw,w)\geq-C_A\|w\|_2^2\). For tangential families
take the supremum of these constants on the compact support of \(\phi\).
Smooth family quantization and the finite seminorm bounds give finite
suprema. For the interior operator the input \((1-\phi)u\) is supported
away from the boundary; insert cutoffs equal to one on that support and
use the same calculation on interior charts. All errors from these
cutoffs are included in \(H_\Lambda\).

At each fixed \(t\), the scalar \(\phi(t)\) commutes with the tangential
operators. It is nonnegative, so multiplying (DA1) by it and integrating
in \(t\) gives the tangential lower bound without taking a square root
of the cutoff. The exact interior quadratic form is
\(\operatorname{Im}(i(1-\phi)\Lambda(1-\phi)u,u)
=\operatorname{Re}(\Lambda(1-\phi)u,(1-\phi)u)\). Combining these
statements with both full identities in (DI6) proves (DI7) with the
concrete choice

\[
 C_b=\max(C_{\Lambda^+},C_{\Lambda^-}),\qquad
 C_i=C_\Lambda,\qquad
 C_P=\|\phi'\|_\infty+2C_b+2C_i.
 \tag{DA2}
\]

No self-adjointness of \(A\) was assumed. Its geometric adjoint has the
same real quadratic form, so the same constants work for \(\Lambda^*\)
and \((\Lambda^\pm)^*\).

To compute \(Q=-P^*\), use the original product metric and density.
Multiplication by the real \(\phi\) is self-adjoint and
\(D_t\phi=\phi D_t-i\phi'\). The full collar adjoint, before exchanging
summands, is

\[
 (P^b)^*=
 \begin{pmatrix}
  \phi D_t-i\phi'-i\phi(\Lambda^+)^*&0\\
  0&-\phi D_t+i\phi'-i\phi(\Lambda^-)^*
 \end{pmatrix},\qquad
 (P^i)^*=-i(1-\phi)\Lambda^*(1-\phi).
 \tag{DA3}
\]

Tangential operators commute with \(\phi(t)\), including when their
coefficients depend on \(t\). Let \(S(v^+,v^-)=(v^-,v^+)\) be the
unitary change of order on the collar. In precisely the order (DI12) the
full operator is

\[
 \begin{aligned}
 SQ^bS^{-1}
 &=\phi\begin{pmatrix}
       D_t+i(\Lambda^-)^*&0\\
       0&-D_t+i(\Lambda^+)^*
      \end{pmatrix}
       +\begin{pmatrix}-i\phi'&0\\0&i\phi'\end{pmatrix},\\
 SQ^iS^{-1}&=i(1-\phi)S\Lambda^*S^{-1}(1-\phi),\\
 B_Qv&=\gamma_0v^+=\gamma_0(Sv)^-.
 \end{aligned}
 \tag{DA4}
\]

The second formula is a collar expression only; it does not assert that
the splitting or \(S\) extends over the whole interior bundle. On the
original bundle the full interior operator is
\(i(1-\phi)\Lambda^*(1-\phi)\). These descriptions give the same
quadratic form on their respective charts. The displayed multiplication
remainder contributes exactly

\[
 2\operatorname{Im}
   \left(\begin{pmatrix}-i\phi'&0\\0&i\phi'\end{pmatrix}
                       v_Q,v_Q\right)
   =-2\int\phi'|v_Q^+|^2+2\int\phi'|v_Q^-|^2.
 \tag{DA5}
\]

Its absolute value is at most \(2\|\phi'\|_\infty\|v\|_2^2\). Therefore
(DI7) holds for \(Q\) with \(C_Q=C_P+2\|\phi'\|_\infty\), with its plus
and minus boundary spaces exactly as in (DI12). A single
\(T>\max(C_P,C_Q)/2\) supplies both estimates used in (DI8) and (DI11).
This proves the shifted bijectivity without discarding either
differentiated-cutoff term.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-004}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-004}\label{AN03-SDI-004}\endgroup\ReaderOriginalAnchorStart{4-a-surjective-boundary-constraint-preserves-the-index}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{4-a-surjective-boundary-constraint-preserves-the-index}\label{4-a-surjective-boundary-constraint-preserves-the-index}\endgroup\ReaderOriginalAnchorStart{a-surjective-boundary-constraint-preserves-the-index}\ReaderOriginalAnchorEnd}
\subsection{4. A surjective boundary constraint preserves the
index}\label{a-surjective-boundary-constraint-preserves-the-index}

Let \(X_0,Y_0,Z_0\) be Hilbert spaces, let
\(A=(P,B):X_0\to Y_0\oplus Z_0\) be Fredholm, and suppose
\(B:X_0\to Z_0\) is surjective. Its restriction to \((\ker B)^\perp\) is
a bounded bijection onto \(Z_0\), so the Banach inverse theorem supplies
a bounded right inverse \(R:Z_0\to X_0\). Set \(X_B=\ker B\). Define

\[
 \begin{aligned}
 J:X_B\oplus Z_0&\longrightarrow X_0,
 &J(x,z)&=x+Rz,\\
 J^{-1}u&=(u-RBu,Bu),\\
 S:Y_0\oplus Z_0&\longrightarrow Y_0\oplus Z_0,
 &S(y,z)&=(y-PRz,z).
 \end{aligned}
 \tag{DI16}
\]

Both \(J\) and \(S\) are bounded isomorphisms, and direct substitution
gives the exact triangular reduction

\[
 SAJ(x,z)=(Px,z),\qquad
 SAJ=(P|_{X_B})\oplus I_{Z_0}.
 \tag{DI17}
\]

It follows that \(P|_{X_B}:X_B\to Y_0\) is Fredholm and that its kernel,
cokernel, and index agree with those of \(A\):

\[
 \ker(P|_{X_B})=\ker A,\qquad
 \operatorname{coker}(P|_{X_B})\simeq\operatorname{coker}A,\qquad
 \operatorname{ind}(P|_{X_B})=\operatorname{ind}A.
 \tag{DI18}
\]

This also proves the cokernel isomorphism, rather than only an index
count.

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\subsection{5. The reflected complementary
half}\label{the-reflected-complementary-half}

Now let \(P_1:E_1\to F_1\) be any elliptic first-order mixed operator on
a copy \(X_1=X\) whose collar part, after a fixed collar identification
\(\kappa:F_1\simeq E_1\), is the split expression in (DI2). Its
compactly supported interior part need not be the positive model used to
prove (DI15). Give a second copy \(X_2=X\) the inward coordinate
\(t_2\geq0\), copy the split bundle \(E_2^+\oplus E_2^-\), and set near
its boundary

\[
 P_2^b=\phi
 \begin{pmatrix}
  -D_{t_2}+i\Lambda^+&0\\
  0&D_{t_2}+i\Lambda^-
 \end{pmatrix},\qquad
 B_2u_2=\gamma_0u_2^+.
 \tag{DI19}
\]

Complete \(P_2^b\) away from the boundary by the reflected version of
the positive interior term in (DI2): choose
\(\Lambda_2\in\Psi_{\mathrm{phg}}^1(X_2^\circ;E_2)\) with positive
scalar principal symbol and set \(P_2^i=i(1-\phi)\Lambda_2(1-\phi)\),
\(P_2=P_2^b+P_2^i\). Its frozen solutions are

\[
 u_2^+(t_2)=e^{-\lambda^+t_2}u_2^+(0),\qquad
 u_2^-(t_2)=e^{\lambda^-t_2}u_2^-(0).
 \tag{DI20}
\]

Thus its stable trace is exactly \(E^+\), and \(B_2\) is the identity
there. After ordering the summands as \(E_2^-\oplus E_2^+\), this is the
model of Section 1. Hence

\[
 \operatorname{ind}(P_2,B_2)=0.
 \tag{DI21}
\]

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-006}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-006}\label{AN03-SDI-006}\endgroup\ReaderOriginalAnchorStart{6-smooth-gluing-of-the-doubled-bundles-and-operator}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{6-smooth-gluing-of-the-doubled-bundles-and-operator}\label{6-smooth-gluing-of-the-doubled-bundles-and-operator}\endgroup\ReaderOriginalAnchorStart{smooth-gluing-of-the-doubled-bundles-and-operator}\ReaderOriginalAnchorEnd}
\subsection{6. Smooth gluing of the doubled bundles and
operator}\label{smooth-gluing-of-the-doubled-bundles-and-operator}

Glue \(X_1\) and \(X_2\) along \(Y\). In the resulting two-sided collar
use the signed coordinate

\[
 r=t_1\quad\hbox{on }X_1,\qquad
 r=-t_2\quad\hbox{on }X_2.
 \tag{DI22}
\]

Glue \(E_1\) to \(E_2\) by the identity on \(E^+\oplus E^-\), producing
\(\widehat E\). Glue \(F_1\) to the target \(E_2\) by the collar
identification \(\kappa\), producing \(\widehat F\). Since
\(D_{t_2}=-D_r\), both collar formulas become

\[
 \widehat P^b=
 \begin{pmatrix}
  D_r+i\Lambda^+&0\\
 0&-D_r+i\Lambda^-
 \end{pmatrix}
 \tag{DI23}
\]

on a full two-sided neighborhood of the seam. The interior terms vanish
on that neighborhood because \(1-\phi=0\) there. Thus all coefficient
jets and the bundle maps match, and the piecewise operator defines

\[
 \widehat P:H^s(\widehat X;\widehat E)
       \longrightarrow H^{s-1}(\widehat X;\widehat F).
 \tag{DI24}
\]

This is a smooth mixed collar operator. It need not be an ordinary
global pseudodifferential operator, because \(\Lambda^\pm\) act only in
the tangential variables near the seam. This proves both the
construction and the distinction between a mixed collar operator and an
ordinary global pseudodifferential operator.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-007}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-007}\label{AN03-SDI-007}\endgroup\ReaderOriginalAnchorStart{7-the-coupling-path-and-the-h-1-gluing-domain}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{7-the-coupling-path-and-the-h-1-gluing-domain}\label{7-the-coupling-path-and-the-h-1-gluing-domain}\endgroup\ReaderOriginalAnchorStart{the-coupling-path-and-the-h1-gluing-domain}\ReaderOriginalAnchorEnd}
\subsection{\texorpdfstring{7. The coupling path and the \(H^1\) gluing
domain}{7. The coupling path and the H\^{}1 gluing domain}}\label{the-coupling-path-and-the-h1-gluing-domain}

At the base level put

\[
 \begin{aligned}
 \mathcal X&=\bar H_1(X_1;E_1)\oplus\bar H_1(X_2;E_2),\\
 \mathcal Y&=L^2(X_1;F_1)\oplus L^2(X_2;E_2),\\
 \mathcal Z&=H^{1/2}(Y;E^+)\oplus H^{1/2}(Y;E^-),\\
 C_\tau(u_1,u_2)&=
 \bigl(\gamma_0u_2^+-\tau\gamma_0u_1^+,
       \gamma_0u_1^--\tau\gamma_0u_2^-\bigr),
       \qquad0\leq\tau\leq1,\\
 \mathcal A_\tau&=(P_1\oplus P_2,C_\tau):
              \mathcal X\longrightarrow\mathcal Y\oplus\mathcal Z.
 \end{aligned}
 \tag{DI25}
\]

The stable traces of \(P_1\oplus P_2\) have the form \((0,a^-;a^+,0)\).
On them,

\[
 C_\tau(0,a^-;a^+,0)=(a^+,a^-),
 \tag{DI26}
\]

independently of \(\tau\). The principal boundary map is therefore an
isomorphism for every parameter. The generalized Fredholm theorem and
homotopy stability give

\[
 \operatorname{ind}\mathcal A_\tau
       =\operatorname{ind}\mathcal A_0
       \qquad(0\leq\tau\leq1).
 \tag{DI27}
\]

The coupling map itself is surjective. For data \((a^+,b^-)\), choose
fixed Sobolev trace extensions with

\[
 \gamma_0u_2^+=a^+,\quad \gamma_0u_1^-=b^-,\quad
 \gamma_0u_1^+=0,\quad \gamma_0u_2^-=0.
 \tag{DI28}
\]

This gives one bounded right inverse \(R:\mathcal Z\to\mathcal X\) for
every \(C_\tau\). Apply (DI18):

\[
 \operatorname{ind}\bigl((P_1\oplus P_2)|_{\ker C_\tau}\bigr)
       =\operatorname{ind}\mathcal A_\tau.
 \tag{DI29}
\]

At \(\tau=0\), the two constraints are \(\gamma_0u_2^+=0\) and
\(\gamma_0u_1^-=0\). After a fixed permutation of the target factors,
the constrained operator is the direct sum of \(P_1|_{\ker B_1}\) and
\(P_2|_{\ker B_2}\). Equation (DI18) identifies their indices with those
of \((P_1,B_1)\) and \((P_2,B_2)\). Equations (DI21), (DI27), and (DI29)
give

\[
 \operatorname{ind}\bigl((P_1\oplus P_2)|_{\ker C_1}\bigr)
 =\operatorname{ind}(P_1,B_1).
 \tag{DI30}
\]

The varying kernels can also be trivialized explicitly. Put

\[
 K(u_1,u_2)=(\gamma_0u_1^+,\gamma_0u_2^-),\qquad
 C_\tau=C_0-\tau K,\qquad KR=0,\qquad C_0R=I_{\mathcal Z}.
 \tag{DI31}
\]

For \(x\in\ker C_0\), define

\[
 J_\tau x=x+\tau RKx.
 \tag{DI32}
\]

Then \(C_\tau J_\tau x=0\). Its inverse on \(\ker C_\tau\) is
\(y\mapsto y-RC_0y\), because \(C_0y=\tau Ky\) and \(KR=0\). Hence
\(J_\tau:\ker C_0\to\ker C_\tau\) is a continuous family of bounded
isomorphisms. This makes the Fredholm deformation in (DI30) an actual
fixed-domain path, not merely an index comparison between unnamed
spaces.

At \(\tau=1\), the constraint is equality of the two full boundary
traces. The exact \(H^1\) gluing identity is

\[
 H^1(\widehat X;\widehat E)
 \simeq\{(u_1,u_2)\in\mathcal X:
        \gamma_0u_1^+=\gamma_0u_2^+,
        \ \gamma_0u_1^-=\gamma_0u_2^-\}
 =\ker C_1.
 \tag{DI33}
\]

One direction follows by restriction. Conversely, the distributional
first derivative of a piecewise \(H^1\) section has a seam delta whose
coefficient is its trace jump; equality of traces removes that delta,
leaving every weak first derivative in \(L^2\). Under (DI33), the
constrained piecewise operator is exactly (DI24). Thus

\[
 \boxed{\operatorname{ind}\widehat P
       =\operatorname{ind}(P_1,B_1)}
 \tag{DI34}
\]

at \(H^1\to L^2\). The statement at this step is deliberately made at
\(s=1\): equality of value traces alone is not the complete gluing
condition for arbitrary higher Sobolev order.

\begin{figure}
\centering
\pandocbounded{\includegraphics[keepaspectratio,alt={The stable summands on the reflected halves, the coupling path, and the two index strata}]{../figures/split_doubling_index.png}}
\caption{The stable summands on the reflected halves, the coupling path,
and the two index strata}
\end{figure}

The left panel keeps both inward coordinates and the signed collar
coordinate visible. The middle panel shows why the boundary symbol stays
invertible throughout the coupling. The right panel records the
complementary index that distinguishes equality from a one-half formula.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-SEAM-001}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-SEAM-001}\label{AN03-SDI-SEAM-001}\endgroup\ReaderOriginalAnchorStart{the-complete-seam-distribution}\ReaderOriginalAnchorEnd}
\subsubsection{The complete seam
distribution}\label{the-complete-seam-distribution}

We verify the asserted gluing in the actual product collar. Use its
signed coordinate \(r=t_1=-t_2\), product density \(d\mu_Y\,dr\), and
the domain-bundle identification from Section 6. In any product frame,
write

\[
 u(y,r)=\begin{cases}
             u_1(y,r),&r>0,\\
             u_2(y,-r),&r<0,
          \end{cases}
 \qquad j(y)=\gamma_0u_1(y)-\gamma_0u_2(y).
 \tag{DG1}
\]

Let \(H\) be the Heaviside function; its value at zero does not affect
the distribution. Integration by parts on each half, with the common
boundary measure, gives every first derivative:

\[
 \begin{aligned}
 D_ru&=H(r)D_{t_1}u_1(y,r)
        -H(-r)D_{t_2}u_2(y,-r)-i j(y)\delta(r),\\
 D_{y_a}u&=H(r)D_{y_a}u_1(y,r)
               +H(-r)D_{y_a}u_2(y,-r),
       \qquad 1\leq a\leq\dim Y.
 \end{aligned}
 \tag{DG2}
\]

For smooth half-sections this follows directly from
\(\partial_rH(r)=\delta(r)\) and \(\partial_rH(-r)=-\delta(r)\). For
half-sections in \(H^1\), approximate on each half by smooth sections.
The continuous \(H^1\to H^{1/2}\) trace map from
\href{mixed-sobolev-mapping.pdf}{Mixed symbols on every real
two-parameter Sobolev scale} makes the seam coefficients converge, while
the half-space functions and weak derivatives converge in \(L^2\).
Pairing with each compactly supported smooth test section passes the
identities to the limit. Thus no differentiability of the traces is
assumed.

All bulk terms in (DG2) are in \(L^2\). If \(j=0\), every weak first
derivative is in \(L^2\), proving the converse in (DI33). If \(j\ne0\),
choose a smooth compactly supported tangential test section \(b\) with
\(\langle j,b\rangle\ne0\). Such a test exists because a nonzero
distribution cannot vanish on every test section. Choose
\(h\in C_c^\infty(\mathbb R)\) with \(h(0)=1\), and put
\(h_\varepsilon(r)=h(r/\varepsilon)\). Then

\[
 \begin{aligned}
 \langle j\delta(r),b(y)h_\varepsilon(r)\rangle
     &=\langle j,b\rangle,\\
 \|b(y)h_\varepsilon(r)\|_{L^2(d\mu_Y\,dr)}
     &=\varepsilon^{1/2}\|b\|_{L^2(d\mu_Y)}\|h\|_{L^2(dr)}.
 \end{aligned}
 \tag{DG3}
\]

An \(L^2\) distribution has pairings bounded by its \(L^2\) norm times
the second line, which tends to zero. The first line is a fixed nonzero
number. Therefore the seam delta is not in \(L^2\). In (DG2) it cannot
cancel an \(L^2\) bulk term. This proves necessity of trace equality as
well.

The restriction map and the piecewise inverse are bounded for the
finite-chart \(H^1\) norms: (DG2) with zero jump bounds every coordinate
first derivative by the two half-norms, and restriction bounds each
half-norm by the global norm. Smooth transition matrices contribute
their actual bounded first derivatives; the fixed product metric and
density compare these finitely many chart norms. This proves the bounded
isomorphism (DI33), including its full domain. It makes no claim that
matching values alone glues higher Sobolev orders, which would require
the corresponding normal-jet conditions.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-008}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-008}\label{AN03-SDI-008}\endgroup\ReaderOriginalAnchorStart{8-approximation-by-ordinary-operators-and-the-symbol-index}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{8-approximation-by-ordinary-operators-and-the-symbol-index}\label{8-approximation-by-ordinary-operators-and-the-symbol-index}\endgroup\ReaderOriginalAnchorStart{approximation-by-ordinary-operators-and-the-symbol-index}\ReaderOriginalAnchorEnd}
\subsection{8. Approximation by ordinary operators and the symbol
index}\label{approximation-by-ordinary-operators-and-the-symbol-index}

In the signed collar let \((\eta,\rho)\) be the covariables dual to
\((y,r)\). The principal symbol of (DI23), extended by the ordinary
interior symbols, is continuous and degree one on
\(T^*\widehat X\setminus0\). At \(\eta=0\), positive homogeneity gives
\(\lambda^\pm(y,0)=0\), so its two collar blocks equal \(\rho\) and
\(-\rho\). Thus it is still invertible there. Denote this continuous
elliptic symbol by

\[
 \widehat p:T^*\widehat X\setminus0
       \longrightarrow
       \operatorname{Hom}(\pi^*\widehat E,\pi^*\widehat F).
 \tag{DI35}
\]

We now verify the operator-norm approximation required by
\href{global-elliptic-symbol-index.pdf}{Symbols, finite defects, and the
index on a closed manifold} rather than inferring it from pointwise
smoothing. Choose the scalar cutoff from
\href{global-elliptic-symbol-index.pdf}{Symbols, finite defects, and the
index on a closed manifold}, Section 10,

\[
 \chi(\eta,\rho)=1\ \text{if }|\rho|\leq\max(1,|\eta|),
 \qquad
 \chi(\eta,\rho)=0\ \text{if }|\rho|\geq2\max(1,|\eta|),
 \tag{DI36}
\]

and for \(0<\varepsilon\leq1\) replace every partial tangential symbol
\(a(y,r,\eta)\) of order one by

\[
 a_\varepsilon(y,r,\eta,\rho)
       =a(y,r,\eta)\chi(\eta,\varepsilon\rho).
 \tag{DI37}
\]

For fixed \(\varepsilon>0\), this is a classical full-variable symbol.
On the total unit cosphere its leading term differs from the continuous
zero extension of the partial leading symbol only where
\(|\eta|\leq2\varepsilon|\rho|\). Since that leading term has size at
most \(C|\eta|\),

\[
 \sup_{|\eta|^2+\rho^2=1}
 \|a_{\varepsilon,1}-a_1\|\leq C\varepsilon.
 \tag{DI38}
\]

The exact partial-operator estimate in Section 10 of
\href{global-elliptic-symbol-index.pdf}{Symbols, finite defects, and the
index on a closed manifold} gives, for every real \(s\),

\[
 \|\operatorname{Op}(a_\varepsilon)-a(y,r,D_y)\|
       _{H^s\to H^{s-1}}\leq C_s\varepsilon.
 \tag{DI39}
\]

Apply this construction in a finite signed-collar atlas. Keep \(D_r\)
and every ordinary interior operator unchanged, and patch with the same
fixed bundle charts and cutoffs. The compactness of \(\widehat X\) turns
the local estimates into ordinary classical operators
\(\widehat P_\varepsilon\) satisfying

\[
 \widehat P_\varepsilon\longrightarrow\widehat P
 \quad\text{in }\mathcal L(H^s,H^{s-1})
 \text{ for every real }s,\qquad
 \widehat p_\varepsilon\longrightarrow\widehat p
 \text{ uniformly on }S^*\widehat X.
 \tag{DI40}
\]

Uniform invertibility of \(\widehat p\) on the compact cosphere makes
\(\widehat p_\varepsilon\) elliptic for all sufficiently small
\(\varepsilon\). The norm-limit theorem and its continuous-symbol
identity, proved in Sections 5 and 8 of that lesson, now give

\[
 \operatorname{ind}\widehat P
       =\operatorname{sind}(\widehat p).
 \tag{DI41}
\]

Because (DI40) is compatible at every Sobolev order, the compatible
norm-limit conclusion in that lesson identifies the same smooth kernel
and adjoint obstruction spaces at all levels. Hence (DI34) and (DI41)
hold for every \(s\geq1\):

\[
 \boxed{\operatorname{ind}(P_1,B_1)_s
       =\operatorname{ind}(\widehat P:H^s\to H^{s-1})
       =\operatorname{sind}(\widehat p).}
 \tag{DI42}
\]

This proves the doubled symbol-index formula with the precise
approximation hypotheses.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-009}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-009}\label{AN03-SDI-009}\endgroup\ReaderOriginalAnchorStart{9-the-two-exact-kinds-of-doubled-index-datum}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{9-the-two-exact-kinds-of-doubled-index-datum}\label{9-the-two-exact-kinds-of-doubled-index-datum}\endgroup\ReaderOriginalAnchorStart{the-two-exact-kinds-of-doubled-index-datum}\ReaderOriginalAnchorEnd}
\subsection{9. The two exact kinds of doubled index
datum}\label{the-two-exact-kinds-of-doubled-index-datum}

Two published index wordings become exact once the complementary half is
made part of the datum. Let \(A:X_A\to Y_A\) be Fredholm. A
\emph{deformation double datum} for \(A\) is a Fredholm operator
\(D:X_D\to Y_D\), a Fredholm complement \(C:X_C\to Y_C\), fixed domain
and target isomorphisms at the two endpoints, and a continuous
fixed-space Fredholm path joining \(D\) to \(A\oplus C\). Homotopy
invariance and direct-sum additivity give the exact morphism from this
space of data to the integers:

\[
 \mathfrak I(D,C)=\operatorname{ind}D
 =\operatorname{ind}A+\operatorname{ind}C.
 \tag{DI43}
\]

There are two mathematically different strata:

\[
 \begin{array}{lll}
 \mathfrak D_0(A)=\{(D,C):\operatorname{ind}C=0\}
 &\Longrightarrow&\operatorname{ind}D=\operatorname{ind}A,\\[1mm]
 \mathfrak D_{=}(A)=\{(D,C):\operatorname{ind}C=\operatorname{ind}A\}
 &\Longrightarrow&\operatorname{ind}D=2\operatorname{ind}A.
 \end{array}
 \tag{DI44}
\]

Equations (DI31)--(DI34) supply all the data for the geometric double:
the fixed-domain path is \((P_1\oplus P_2)J_\tau\), its endpoint
complement is \((P_2,B_2)\), and (DI21) gives its index zero. Therefore
the concrete operator \(\widehat P\) belongs to
\(\mathfrak D_0(P_1,B_1)\), and its formula is the equality in (DI42).

A one-half formula is valid only after a separately specified double
datum is proved to lie in \(\mathfrak D_{=}(A)\):

\[
 \operatorname{ind}A=\frac12\operatorname{ind}D
 \quad\Longleftrightarrow\quad
 \operatorname{ind}C=\operatorname{ind}A
 \quad\text{within a deformation double datum.}
 \tag{DI45}
\]

Thus the introductory one-half wording cannot be applied to the operator
\(\widehat P\) constructed here. The zero-index complementary half
proved in (DI21) gives equality. A summary using one half must name and
prove a different same-index complement and its deformation data.
Without that information the one-half statement is underdetermined; it
is not a replacement for (DI42). This is the exact conceptual
correction. It keeps the equality theorem and the conditional one-half
formula attached to their respective doubled constructions.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-010}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-010}\label{AN03-SDI-010}\endgroup\ReaderOriginalAnchorStart{10-scalar-sign-check}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{10-scalar-sign-check}\label{10-scalar-sign-check}\endgroup\ReaderOriginalAnchorStart{scalar-sign-check}\ReaderOriginalAnchorEnd}
\subsection{10. Scalar sign check}\label{scalar-sign-check}

For \(E^+=E^-=\mathbb C\) and \(\Lambda^+=\Lambda^-=|D_y|\), the
first-half stable mode is \((0,e^{-|\eta|t_1}a^-)\), while the
second-half stable mode is \((e^{-|\eta|t_2}a^+,0)\). The coupling gives

\[
 C_\tau(0,e^{-|\eta|t_1}a^-;
        e^{-|\eta|t_2}a^+,0)=(a^+,a^-).
 \tag{DI46}
\]

In the signed coordinate, both halves have symbol
\(\operatorname{diag}(\rho+i|\eta|,-\rho+i|\eta|)\). This checks the
reflection sign, the stable summands, the order of the coupling
components, and the seam compatibility in one calculation.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-011}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-011}\label{AN03-SDI-011}\endgroup\ReaderOriginalAnchorStart{11-three-concrete-models}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{11-three-concrete-models}\label{11-three-concrete-models}\endgroup\ReaderOriginalAnchorStart{three-concrete-models}\ReaderOriginalAnchorEnd}
\subsection{11. Three concrete models}\label{three-concrete-models}

\ReaderArmAliases{\ReaderOriginalAnchorStart{a-finite-dimensional-boundary-constraint}\ReaderOriginalAnchorEnd}
\subsubsection{A finite-dimensional boundary
constraint}\label{a-finite-dimensional-boundary-constraint}

Take \(X_0=\mathbb C^3\), \(Y_0=\mathbb C^2\), \(Z_0=\mathbb C\), and

\[
 P(x_1,x_2,x_3)=(x_1,x_2+x_3),\qquad B(x_1,x_2,x_3)=x_3.
 \tag{DI47}
\]

The combined map \((P,B)\) is invertible. On \(\ker B\), the restricted
map is \((x_1,x_2,0)\mapsto(x_1,x_2)\), also invertible. The right
inverse \(Rz=(0,0,z)\) makes (DI16)--(DI17) an ordinary triangular
matrix factorization. This finite model displays the exact cokernel
isomorphism used for Sobolev boundary spaces.

\ReaderArmAliases{\ReaderOriginalAnchorStart{why-matching-values-is-the-right-h1-condition}\ReaderOriginalAnchorEnd}
\subsubsection{\texorpdfstring{Why matching values is the right \(H^1\)
condition}{Why matching values is the right H\^{}1 condition}}\label{why-matching-values-is-the-right-h1-condition}

Let \(u_1\in H^1([0,1])\) and \(u_2\in H^1([-1,0])\), and join them as a
piecewise function \(u\). For every compactly supported smooth test
function \(\varphi\), integration by parts on the two halves gives

\[
 \langle \partial_ru,\varphi\rangle
 =\int_{-1}^0u_2'\varphi\,dr+\int_0^1u_1'\varphi\,dr
  +(u_1(0)-u_2(0))\varphi(0).
 \tag{DI48}
\]

The distributional derivative lies in \(L^2\) exactly when the trace
jump vanishes. This is the one-dimensional form of (DI33). Higher
Sobolev gluing needs further matching derivatives, which is why the
index identification is first made at \(H^1\to L^2\).

\ReaderArmAliases{\ReaderOriginalAnchorStart{the-angular-cap-estimate}\ReaderOriginalAnchorEnd}
\subsubsection{The angular cap estimate}\label{the-angular-cap-estimate}

For the scalar partial symbol \(a(\eta)=|\eta|\), the leading-symbol
difference in (DI37) is supported where
\(|\eta|\leq2\varepsilon|\rho|\). On \(|\eta|^2+\rho^2=1\),

\[
 |a_{\varepsilon,1}-a_1|\leq|\eta|\leq2\varepsilon.
 \tag{DI49}
\]

This is the exact small factor that turns the tangential operator into
an operator-norm limit of ordinary full-variable pseudodifferential
operators.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-012}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-012}\label{AN03-SDI-012}\endgroup\ReaderOriginalAnchorStart{12-exercises-with-complete-solutions}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{12-exercises-with-complete-solutions}\label{12-exercises-with-complete-solutions}\endgroup\ReaderOriginalAnchorStart{exercises-with-complete-solutions}\ReaderOriginalAnchorEnd}
\subsection{12. Exercises with complete
solutions}\label{exercises-with-complete-solutions}

\textbf{1. Recover the two endpoint signs.} Starting from
\(D_t=-i\partial_t\), prove (DI6) without assuming that \(w\) is scalar.

\textbf{Solution.} The fiber metric gives
\(\partial_t|w|^2=(\partial_tw,w)+(w,\partial_tw)\). Hence

\[
 \begin{aligned}
 2i\operatorname{Im}(\phi D_tw,w)
 &=-i\int_0^\infty\phi\,\partial_t|w|^2dt\\
 &=i|w(0)|^2+i\int_0^\infty\phi'|w|^2dt.
 \end{aligned}
 \tag{DI50}
\]

Divide by \(i\). Replacing \(D_t\) by \(-D_t\) reverses both terms. The
calculation is component-free, so it holds for bundle-valued \(w\).

\textbf{2. Check the cokernel multiplier.} In (DI10), use arbitrary
minus traces to recover the exact formula for \(h\).

\textbf{Solution.} For \(a=\gamma_0u^-\), the minus terms are
\(-i(a,\gamma_0v^-)+(a,h)\). Since the inner product is linear in the
first entry, \((a,i\gamma_0v^-)=-i(a,\gamma_0v^-)\). Vanishing for every
\(a\) gives

\[
 h+i\gamma_0v^-=0,\qquad h=-i\gamma_0v^-.
 \tag{DI51}
\]

\textbf{3. Verify the triangular reduction.} Prove directly that the
maps \(J\) and \(S\) in (DI16) are invertible and calculate \(SAJ\).

\textbf{Solution.} Because \(BR=I\), \(u-RBu\in\ker B\), so the
displayed formula for \(J^{-1}\) is defined. Direct substitution gives
\(J^{-1}J(x,z)=(x,z)\) and \(JJ^{-1}u=u\). The inverse of \(S\) is
\(S^{-1}(y,z)=(y+PRz,z)\). Finally,

\[
 SAJ(x,z)=S(Px+PRz,z)=(Px,z).
 \tag{DI52}
\]

\textbf{4. Trivialize the coupling kernels.} Prove that \(J_\tau\) in
(DI32) maps \(\ker C_0\) bijectively onto \(\ker C_\tau\).

\textbf{Solution.} For \(x\in\ker C_0\), use \(C_\tau=C_0-\tau K\),
\(C_0R=I\), and \(KR=0\):

\[
 C_\tau(x+\tau RKx)=0+\tau Kx-\tau Kx-\tau^2KRKx=0.
 \tag{DI53}
\]

If \(y\in\ker C_\tau\), then \(C_0y=\tau Ky\). Put \(x=y-RC_0y\). This
lies in \(\ker C_0\), \(Kx=Ky\), and \(x+\tau RKx=y\). Thus
\(y\mapsto y-RC_0y\) is the inverse.

\textbf{5. Test the two index strata.} Let \(\operatorname{ind}A=-3\).
Compute the doubled index for a zero-index complement and for a
same-index complement.

\textbf{Solution.} Equation (DI43) gives

\[
 \operatorname{ind}D=
 \begin{cases}
 -3,&\operatorname{ind}C=0,\\
 -6,&\operatorname{ind}C=-3.
 \end{cases}
 \tag{DI54}
\]

The first construction gives equality. The second gives
\(\operatorname{ind}A=\frac12\operatorname{ind}D=-3\). Moving the factor
\(1/2\) between these two data would give the wrong integer.

\textbf{6. Why must the approximation be in operator norm?} Explain why
pointwise convergence of the full symbols in (DI37) would not by itself
prove the index identity.

\textbf{Solution.} Fredholm index stability applies to bounded operators
in their operator-norm topology. Pointwise symbol convergence gives no
uniform control on the maps between Sobolev spaces and does not exclude
a loss concentrated in a shrinking angular cap. The partial-operator
estimate supplies the needed bound:

\[
 \|\widehat P_\varepsilon-\widehat P\|_{H^s\to H^{s-1}}
 \leq C_s\varepsilon.
 \tag{DI55}
\]

Together with uniform principal-symbol convergence and ellipticity, this
is exactly the hypothesis of the norm-limit index theorem.

\ReaderArmAliases{\ReaderOriginalAnchorStart{AN03-SDI-013}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{AN03-SDI-013}\label{AN03-SDI-013}\endgroup\ReaderOriginalAnchorStart{13-reading-notes-and-references}\ReaderOriginalAnchorEnd\begingroup\expandafter\def\csname @currentHref\endcsname{13-reading-notes-and-references}\label{13-reading-notes-and-references}\endgroup\ReaderOriginalAnchorStart{reading-notes-and-references}\ReaderOriginalAnchorEnd}
\subsection{13. Reading notes and
references}\label{reading-notes-and-references}

Equations (DI43)--(DI45) identify the missing datum and give the exact
correction for the actual chosen complementary half.

\href{stable-boundary-models.pdf}{Stable modes and the algebra of
boundary data} proves the stable-space algebra used in Sections 1 and 5.
\href{generalized-collar-fredholm.pdf}{Fredholm boundary problems with
first-order Calderón defects} supplies the generalized Fredholm and
regularity theorem. \href{global-elliptic-symbol-index.pdf}{Symbols,
finite defects, and the index on a closed manifold} proves the
partial-operator approximation and continuous symbol-index theorem used
in Section 8.

The arguments, examples, figure, and exercises in this lesson are
independently written. No historical source correspondence beyond the
cited statement locations is asserted.

Written and dedicated to the public domain by Codex under CC0 1.0.

\end{document}
